17. A local bus is carrying 40 passengers, some with Rs 5 tickets and the remaining with Rs 7.50 tickets. If the total receipts from these passengers are Rs 230, find the number of passengers with Rs 5 tickets.

Solution: Let the number of passengers with Rs 5 tickets = x Then, the number of passengers with Rs 7.50 tickets = (40 – x) According to the given statement, 5 × x + (40 – x) × 7.50 = 230 On simplification, we get, 5x + 300 – 7.5x = 230 5x – 7.5x = 230 – 300 -2.5x = – 70 x = -70 / – 2.5 We get, x = 28 Therefore, the number of passengers with Rs 5 tickets = 28