Which of the following best explains the value of sin on the unit circle below? sin frac π 3= 0pposite/hypotenuse = opposite/1 opposite The length opposite the angle is the vertical distance from the x-axis on the graph. sin frac π 3= adjacent/hypotenuse = adjacent/1 =adjacent The length adjacent to the angle is the vertical distance from the x-axis on the graph. sin frac π 3= 0ppoosite/pppotenuse = 0pposite/1 opposite The length opposite the angle is the horizontal distance from the y-axis on the graph. sin frac π 3=frac adacenthypotenuse= adjacent/1 =adjacent The length adjacent to the angle is the horizontal distance from the y-axis on the graph. _

Question
Which of the following best explains the value of sin on the unit circle below? sin frac π 3= 0pposite/hypotenuse = opposite/1 opposite The length opposite the angle is the vertical distance from the x-axis on the graph. sin frac π 3= adjacent/hypotenuse = adjacent/1 =adjacent The length adjacent to the angle is the vertical distance from the x-axis on the graph. sin frac π 3= 0ppoosite/pppotenuse = 0pposite/1 opposite The length opposite the angle is the horizontal distance from the y-axis on the graph. sin frac π 3=frac adacenthypotenuse= adjacent/1 =adjacent The length adjacent to the angle is the horizontal distance from the y-axis on the graph. _
Answer:
Which of the following best explains the value of sin on the unit circle below? sin frac π 3= 0pposite/hypotenuse = opposite/1 opposite The length opposite the angle is the vertical distance from the x-axis on the graph. sin frac π 3= adjacent/hypotenuse = adjacent/1 =adjacent The length adjacent to the angle is the vertical distance from the x-axis on the graph. sin frac π 3= 0ppoosite/pppotenuse = 0pposite/1 opposite The length opposite the angle is the horizontal distance from the y-axis on the graph. sin frac π 3=frac adacenthypotenuse= adjacent/1 =adjacent The length adjacent to the angle is the horizontal distance from the y-axis on the graph. _ 65105833710fe.webp
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algebra 5 months ago 8435