Assume that the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed. What is the probability that a test taker scores at least 1600 on the test? Round your answer to two decimal places.

Answer:0.00Step-by-step explanation:If the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed, to calculate the probability that a test taker scores at least 1600 on the test, we should first to calculate the z-score related to 1600. This z-score is [tex]z=\frac{1600-1010}{200}=2.95[/tex], then, we are seeking P(Z > 2.95), where Z is normally distributed with mean 0 and standard deviation 1. Therefore, P(Z > 2.95) = 0.00