What is the equation of a line that is parallel to -x+3y=6 and passes through the point (3,5)?Enter your awnser in the box.For a test!!

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:Where:m: It's the slopeb: It is the cut-off point with the y axisBy definition, if two lines are parallel then their slopes are equal.We have the following line:[tex]-x + 3y = 6\\3y = x + 6\\y = \frac {1} {3} x + \frac {6} {3}\\y = \frac {1} {3} x + 2[/tex]Thus, the slope is:[tex]m_ {1} = \frac {1} {3}[/tex]Then [tex]m_ {2} = \frac {1} {3}[/tex]So, the line is of the form:[tex]y = \frac {1} {3} x + b[/tex]We substitute the point[tex](x, y) :( 3,5)[/tex]and find b:[tex]5 = \frac {1} {3} (3) + b\\5 = b[/tex]Thus, the equation is:[tex]y = \frac {1} {3} x + 5[/tex]Answer:[tex]y = \frac {1} {3} x + 5[/tex]