What is the first step in writing fx=3x2+6x-8 in vertex form? Factor out 3 from each term. Form a perfect square trinomial by keeping the value of the function equivalent. Write the trinomial as a binomial squared. Factor out 3 from the first two terms.

Write properties of function: vertex form: f{(x )} = 3 (x + 1)^{2} - 11vertex form: f{(x )} = 3 (x + 1)^{2} - 11vertex: (-1,-11)vertex: (-1,-11)factorized form: no