What values of b satisfy 32b+32=36 ? b=frac -3+2 square root of 32 and frac -3-2 square root of 32 b=frac -3+2 square root of 33 and frac -3-2 square root of 33 b= 3/2 and - 9/2 b= 9/2 and - 3/2

Question

$What values of b satisfy 32b+32=36 ? b=frac -3+2 square root of 32 and frac -3-2 square root of 32 b=frac -3+2 square root of 33 and frac -3-2 square root of 33 b= 3/2 and - 9/2 b= 9/2 and - 3/2$

Answer:

b = \dfrac{2 \sqrt{3} - 3}{2} or b = - \dfrac{2 \sqrt{3} + 3}{2}

solved

algebra 11 months ago 1326