Write 6x-54+4x-52+6=0 in the form of a quadratic by using substitution. 6u2+4u+6=0 , where u=x-5 6u2+4u+6=0 , where u=x-52 6u4+4u+6=0 , where u=x-55 6u4+4u+6=0 , where u=x-52

Question
Write 6x-54+4x-52+6=0 in the form of a quadratic by using substitution. 6u2+4u+6=0 , where u=x-5 6u2+4u+6=0 , where u=x-52 6u4+4u+6=0 , where u=x-55 6u4+4u+6=0 , where u=x-52
Answer:
Write 6x-54+4x-52+6=0 in the form of a quadratic by using substitution. 6u2+4u+6=0 , where u=x-5 6u2+4u+6=0 , where u=x-52 6u4+4u+6=0 , where u=x-55 6u4+4u+6=0 , where u=x-52 65047e96542bc.webp
solved
algebra 11 months ago 8763