6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions

Answer:h = 2Step-by-step explanation:6x  + 18  =  h (3x + 9)To get the value of h, we simply need to make h subject of the formula;To make h subject of the formula, we simply divide both-side of the equation by (3x + 9)[tex]\frac{6x + 18}{3x + 9}[/tex]       =     [tex]\frac{h(3x + 9)}{(3x + 9)}[/tex](On the right hand side of the equation (3x+2) will cancel out (3x+2) leaving us with h)[tex]\frac{6x + 18}{3x + 9}[/tex]       =      hh  =   [tex]\frac{6x + 18}{3x + 9}[/tex]   ----------------(1)We want to make the numerator and denominator look the same so that  we can cancel out, at the numerator, we can factor out 2 from 6x + 18i.e 6x + 18 = 2 ( 3x + 9)So we can  replace 6x + 18    by  2(3x + 9)  in equation (1)h = [tex]\frac{2 (3x + 9)}{(3x +9)}[/tex]( on the right hand side of the equation, (3x + 9) will cancel out (3x + 9) leaving us with just 2)h = 2We can plug in our h =2 in the initial equation6x +  18   =  2(3x + 9)6x + 18 = 6x + 18This equation has an infinite number of solutions.Therefore the value of constant h in the equation that can make the equation have an infinite number of solutions is 2