A ball is thrown directly upward from a height of 7 feet with an initial velocity of 50 ft./s use the quadratic formula to find the number of seconds it takes the ball to hit the ground

Answer:The time taken by ball to hit the ground is 5.10 seconds .Step-by-step explanation:Given as :The height cover by ball to move upward = 7 feetThe initial velocity = u = 50 feet per secLet the time taken by ball to hit the ground = t secLet the deacceleration rate = - 9.8 m/s²The final velocity of the ball = v=  0 at the topSo, From equationv = u + atI.e v = u + a × tOr, 0 = 50 + ( - 9.8) × tOr, 9.8 t = 50∴ t = [tex]\frac{50}{9.8}[/tex] I.e t = 5.10 secondsSo, time taken = 5.10 secHence The time taken by ball to hit the ground is 5.10 seconds . Answer