A basketball​ player's hang time is the time spent in the air when shooting a basket. The formula [tex]t= \frac{ \sqrt{d} }{2} [/tex] models hang​ time, t, in​ seconds, in terms of the vertical distance of a​ player's jump,​ d, in feet. When a particular player dunked a​ basketball, his hang time for the shot was approximately 1.09 seconds. What was the vertical​ distance, d, of his​ jump, rounded to the nearest​ tenth?

Question
Answer:
As with any problem involving formulas, fill in the information you have and solve for the remaining variable.
.. 1.09 = [tex] \frac{ \sqrt{d}}{2} [/tex]
.. [tex] (2 \times 1.09)^{2} = d [/tex]
.. d ≈ 4.8 . . . . feet
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