A basketball player's hang time is the time spent in the air when shooting a basket. The formula [tex]t= \frac{ \sqrt{d} }{2} [/tex] models hang time, t, in seconds, in terms of the vertical distance of a player's jump, d, in feet. When a particular player dunked a basketball, his hang time for the shot was approximately 1.09 seconds. What was the vertical distance, d, of his jump, rounded to the nearest tenth?

Question

Answer:

As with any problem involving formulas, fill in the information you have and solve for the remaining variable.
.. 1.09 = [tex] \frac{ \sqrt{d}}{2} [/tex]
.. [tex] (2 \times 1.09)^{2} = d [/tex]
.. d ≈ 4.8 . . . . feet

solved

general 10 months ago 5625