A box was measured with a degree of accuracy to the nearest 2cm; 24cm Γ 24cm Γ 20cm. What is the smallest possible volume of the box to the nearest cm3?
Question
Answer:
Each measurement is accurate to 2cm so they can each be βoffβ by 2. Since we want the smallest possible volume letβs assume each is actually 2 less than what is given.The sides would then measure: 22, 22 and 18cm respectively. We obtain the volume by multiplying length, width and height...the three values given.
Thus the smallest volume is 22x22x18=8,712 cm^3
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