A jump rope held stationary by two children, one at each end, hangs in a shape that can be modeled by the equation h=0.01x^2 - x + 28, where h is the height (in inches) above the ground and x is the distance (in inches) along the ground measured from the horizontal position of one end. How close to the ground is the lowest part of the rope?
Question
Answer:
the lowest height of a parabola ax²+bx+c is when x=-b/2ain this case, b=-1, a=0.01, so x=1/0.02=50
when x=50, h=0.01*50²-50+28=3
so the lowest part of the rope is 3 feet inches above the ground.
solved
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5 months ago
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