A pizzeria sells pizza according to size:small pizzas cost 10$, medium pizzas 15$ and large pizzas cost 40$. They usually sell as many small pizzas as medium and large pizzas combined. The number of medium pizzas sold is usually twice as many as large ones. How many of each size pizza must they sell to get 600$.

Answer:6 large, 12 medium and 18 smallStep-by-step explanation:Lets call small pizzas s, medium pizzas m and large pizzas l, with its respective prices $10, $15 and $40. As they sell as many small as medium and large combined we can say that:s = m + l [eq 1]Also, as the number of medium is twice the larges we can say that:m = 2l [eq 2]Finally, as the get $600 we know that every amount sold multiplied by its price, and summing all together must bring $600:10s + 15m + 40l = 600 [eq 3]Lets replace s by its value in eq 1:10s + 15m + 40l = 10 (m+l) 15m + 40l = 10m +10l + 15m + 40l = 60025m + 50l = 600Now we can replace m by its value in eq 2:25m + 50l = 25 (2l) + 50 l = 50l + 50l = 100l = 600100l = 600Now divide both sides by 100:l = 6So, 6 large pizzas were sold. Replace l=6 in eq 2:m = 6*2m = 1212 medium pizzas were sold.Finally, replace l=6 and m=12 in eq 1s = m + l = 12 + 6 = 18And 18 small pizzas were sold.Lets verify our results in eq. 3:10*(18) + 15*(12) + 40*(6) = 600180 + 180 + 240 = 600360 + 240 = 600 ---> Verified!