A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Use mc033-1.jpg. 0.327 M 4.29 M 6.00 M 7.35 M

Question
Answer:
Answer: The concentration of the stock solution will be 6.00 M.Explanation: To calculate the molarity of the stock solution we use the formula:[tex]M_1V_1=M_2V_2[/tex]where, [tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the stock solution.[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of the HCl solution.Given:[tex]M_1=?M\\V_1=35mL\\M_2=1.40M\\V_2=150mL[/tex]Putting values in above equation, we get:[tex]M_1\times 35=1.40\times 150[/tex][tex]M_1=6M[/tex]So, the concentration of the stock solution is 6M.
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