An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 20mL. The height of the water rose to 30.2mL. If the mass of the stone was 25g what was its density?

Answer:
density = 2.4509 g/ml

Explanation:
1- getting the volume of the stone:
since the stone has an irregular shape, the volume of the stone would be equal to the increase in the volume of the stone after placing the stone in it.
Initial volume of water = 20 ml
Final volume of water = 30.2 ml
volume of stone = final volume of water - initial volume of water
volume of stone = 30.2 - 20 = 10.2 ml

2- getting the density of the stone:
we have:
volume of stone = 10.2 ml
mass of stone = 25 g
Therefore, we can get the density as follows:
density = mass / volume
density = 25 / 10.2
density = 2.4509 g/ml

Hope this helps :)