Answer please i dont wanna fail this test

Answer is C.

Explanation:

So we have 100 data, aka numbers. So the mean would be
[tex]\dfrac{x_1 + x_2 + x_3 + \cdots + x_{100}}{100} = 267[/tex]

where bunch of x represents those data.

So then [tex]x_1 + x_2 + \cdots + x_{100} = 267\cdot100[/tex], right?

So we have six outliers with mean 688. That would be
[tex]\dfrac{x_{i_1} + x_{i_2} + \cdots + x_{i_6}}6 = 688[/tex]

So then [tex]x_{i_1} + x_{i_2} + \cdots + x_{i_6} = 688\cdot6[/tex]

Now we don't know what i₁, i₂, etc, but we can just subtract outliers from set of observations and we will know that outliers will be gone in set of observation.

So that would be
[tex](x_1 + \cdots + x_{100})- (x_{i_1} + \cdots + x_{i_6}) = 267\cdot100 - 688\cdot6[/tex]

Now we know that there are now 94 remaining observations. So to find mean, we just divide whole thing by 94.

[tex]\dfrac{(x_1 + \cdots + x_{100})- (x_{i_1} + \cdots + x_{i_6})}{94} = \dfrac{267\cdot100 - 688\cdot6}{94} = \boxed{240.12766}[/tex]

Which matches C.

Hope this helps.