Can someone please help me?GEORGINA WAS GIVEN THAT THE LENGTH OF THE RECTANGLE WAS 2.5 INCHES LONGER THEN ITS WIDTH AND THE PERIMETER OF THE RECTANGLE WAS 75.4 INCHES.FIND THE LENGTH AND WIDTH OF THE RECTANGLE Alegebraically. SHOW ALL WORK​

Answer:Length of the rectangle is [tex]18.85\ inches[/tex],and the width of the rectangle is [tex]16.35\ inches[/tex]Step-by-step explanation:Let the width of the rectangle be [tex]x[/tex] inchesThen The length of the rectangle will be [tex]x+2.5[/tex] inchesSo perimeter [tex]=2(length + width)[/tex]Plugging the values:⇒ [tex]2(x+x+2.5)=75.4[/tex]⇒ [tex]2(2x+2.5)=75.4[/tex]⇒ [tex]4x+10=75.4[/tex]   Subtracting [tex]10[/tex] from both sides.⇒ [tex]4x=65.4[/tex]⇒ [tex]x=\frac{65.4}{4}=16.35\ inches[/tex]   So the width of the rectangle is [tex]16.35\ inches[/tex]    And the length of the rectangle is [tex]18.85\ inches[/tex]