Determine the vertex number of a polyhedron with six quadrancular faces
Question
Answer:
A polyhedron with six quadrilateral faces is a type of polyhedron called a **hexahedron**. Hexahedra are three-dimensional shapes with six faces. If we know that each face is a quadrilateral, it means each face is a four-sided polygon.
To determine the number of vertices in a hexahedron, we'll follow these steps:
1. **Euler's Formula for Polyhedra:**
Euler's formula relates the number of vertices (V), edges (E), and faces (F) of a polyhedron. It is given by:
V - E + F = 2
For a hexahedron, we know F = 6, because there are six faces. We're trying to find V, so we have:
V - E + 6 = 2
2. **Determine the Number of Edges:**
Since each face is a quadrilateral (four-sided polygon), each face has four edges. Therefore, the total number of edges in a hexahedron is:
E = 4 * 6 = 24
3. **Substitute E into Euler's Formula:**
Plugging in E = 24, we have:
V - 24 + 6 = 2
4. **Solve for V:**
Rearrange the equation to isolate V:
V - 18 = 2
V = 20
So, a hexahedron (polyhedron with six quadrilateral faces) has 20 vertices.
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