factor 64x^12+27y^3 completely.
Question
Answer:
64 is 4^3x^12 is (x^4)^3
27 is 3^3
using the formula (a^3+b^3)=a^2-ab+b^2), we have
(4x^4+3y)(16x^8-12x^4y+9y^2)
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10 months ago
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