Find the resultant of these two vectors: 2.00 x 102 units due east and 4.00 x 102 units 30.0° north of west.

If two vectors are represented both in magnitude and direction by the two adjacent sides of a triangle taken in an order, then their resultant is given by the third side taken in the reverse order. Resultant vector :                           R = sqrt of A^2 + B^2 + 2ABcosθ given :            A = 200 units            B = 300 units            θ = 30 degrees ∴ R = sqrt of 200^2 + 300^2 + 2(200)(300)cos35 the answer is 477.805656