Find the volume v obtained by rotating the region bounded by the given curves about the specified axis. y = 9 sin x, y = 0, π 2 ≤ x ≤ π; about the x−axis

The volume obtained by rotating the region is 9 cubic units.How to find the volume of a solid of revolutionThe volume of a solid of revolution ([tex]V[/tex]) generated about the x-axis is determined by the following integral formula:[tex]V = \pi \int\limits^{\pi}_{\frac{\pi}{2} } {f(x)} \, dx[/tex] (1)Where [tex]f(x)[/tex] is the curve function. If we know that [tex]f(x) = 9\cdot \sin x[/tex], then the volume of the solid of revolution is:[tex]V = 9\int\limits^\pi_{\frac{\pi}{2} } {\sin x} \, dx[/tex][tex]V = 9\cdot [-\cos \pi + \cos \frac{\pi}{2} ][/tex][tex]V = 9[/tex]The volume obtained by rotating the region is 9 cubic units. [tex]\blacksquare[/tex]RemarkThe statement presents typing mistakes and is poorly formatted. Correct form is shown below:Find the volume [tex]V[/tex] obtained by rotating the region bounded by the given curves about the specified axis. [tex]y = 9\cdot \sin x[/tex], [tex]y = 0[/tex], [tex]\frac{\pi}{2}\le x \le \pi[/tex], about the x-axis.To learn more on solids of revolution, we kindly invite to check this verified question: