For f(x)= 3x+1 and g(x)= x^2-6, find (g/f)(x).A. 3x+1/x^2-6 , x≠ ±√6B. 3x+1/x^2-6C. x^2-6/3x+1D. x^2-6/3x+1, x≠ -1/3

D. The exclusion is important because we cannot divide by zero. Apart from that we are simply looking at a function.