If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle? A) (x + 4)2 + (y + 2)2 = 5 B) (x − 4)2 + (y − 2)2 = 5 C) (x + 4)2 + (y + 2)2 = ✔️ 5 D) (x − 4)2 + (y − 2)2 = ✔️ 5

the center of the circle = (6 + 2)/2 ,  (3 + 1)/2  = (4,2)

diameter = sqrt ( (6-2)^2 + (3-1)^2 ) = sqrt20

radius 1/2 * sqrt20 =  1/2 * 2 * sqrt5 = sqrt 5
r^2 = 5  

so the required equation is:-
(x - 4)^2 + (x - 2)^2 = 5


Its D