In ΔABC, ∠CAD = 22° and segment CB = 15 cm. If the cos of 22° = 0.9272, then the sin of ∠C = _______.
Question
Answer:
You can calculate [tex]\sin22^{\circ}[/tex] using formula: [tex]\cos^222^{\circ}+\sin^222^{\circ}=1[/tex].
Then [tex]\sin^222^{\circ}=1-\cos^222^{\circ}[/tex] and
[tex]\sin^222^{\circ}=1-( 0.9272)^2=0.14030016 \\ \sin22^{\circ}= \sqrt{0.14030016} =0.3746[/tex].
Answer: [tex]\sin22^{\circ}=0.3746[/tex]
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