In the diagram, what is AC?A. 6B. 12.33C. 10D. 12

The exercise is solved by applying the Pythagorean Theorem: h^2= a^2 + b^2  h= √(a^2 + b^2) h: hypotenuse (the opposite side of the right angle and the longest side of the triangle). a and b: legs (the sides that form the right angle). The first objective will be to find the value of AD: AD= AB - DB We don't know the DB leg, so we proceed to find it clearing it from the Pythagorean equation:  h^2= a^2 + b^2 a= √ (h^2 - b^2) a= √ (17^2 - 8^2) a= DB= 15 Then, AD is: AD= 21-15= 6 Once we find the value of the AD leg, we can find the hypotenuse AC: h= √ (a^2 + b^2) h= √ (6^2 + 8^2) h= AC= 10  The answer is: C. 10