Joy needs to mix a 20% acid solution with a 60% acid solution to create 100 millileters of a 28% solution. How many millileters of each solution must Joy use?

Answer:Joy must use 80 milliliters of solution at 20% and 20 milliliters of solution at 60%Step-by-step explanation:Letx -----> milliliters of solution at 20%y -----> milliliters of solution at 60%we know that[tex]x+y=100[/tex] ----> equation A[tex]20\%=20/100=0.20[/tex][tex]60\%=60/100=0.60[/tex][tex]28\%=28/100=0.28[/tex]so[tex]0.20x+0.60y=0.28(x+y)[/tex][tex]0.20x+0.60y=0.28(100)[/tex][tex]0.20x+0.60y=28[/tex] ----> equation BSolve the system of equations by graphingRemember that the solution of the system is the intersection point both graphsThe solution is the point (80,20)see the attached figurethereforeJoy must use 80 milliliters of solution at 20% and 20 milliliters of solution at 60%