Kayla wants to find the width, AB, of a river. She walks along the edge of the river 100ft and marks point C. Then she walks 22ft further and marks point D. She turns 90 degrees and walks until her location, point A, and point C are collinear. She marks point E at this location, as shown.(A) Can Kayla conclude that triangle ABC and triangle EDC are similar? Why or why not? (B) Suppose DE = 32ft. What can Kayla conclude about the width of the river? Explain.Please help?

Answer:Part A) The triangles ABC and EDC are similar, because the three internal angles are equal in both trianglesPart B) The width of the river is about [tex]145.45\ ft[/tex]Step-by-step explanation:we know thatIf two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruentPart A) we know thatThe triangles ABC and EDC are similar, because the three internal angles are equal in both trianglesso[tex]m<DCE=m<ACB[/tex] -----> by vertical angles[tex]m<EDC=m<ABC[/tex] -----> is a right angle[tex]m<DEC=m<CAB[/tex] -----> the sum of the internal angles must be equal to [tex]180[/tex] degreesPart B) we know thatThe triangles ABC and EDC are similar -------> see Part Atherefore[tex]\frac{BC}{DC}=\frac{AB}{DE}[/tex]substitute the values and solve for AB[tex]\frac{100}{22}=\frac{AB}{32}[/tex][tex]AB=32*(\frac{100}{22})=145.45\ ft[/tex]