Kent has a collection of pennies and nickels with a value of 1.98$. the number of pennies he has is five less than twice the number of nickels. how many of each coin does Kent have?1 define your variables ,- what are you solving for2 set up equations - using the information given 3 solve the system using your method of choice

Answer with Step-by-step explanation:We are given that:Kent has a collection of pennies and nickels with a value of 1.98$. The number of pennies he has is five less than twice the number of nickels.  1. Let p be the number of penniesand n be the number of nickles2. Then, p=2n-51 pennie=$0.011 nickle=$0.050.01p+0.05n=1.98Multiplying both sides by 100,we getp+5n=1983. Putting p=2n-5 in p+5n=198,we get2n-5+5n=1987n=198+57n=203n=29Putting value of n in p=2n-5, we getp=2×29-5 p= 58-5 p= 53Hence, Number of pennies=53and number of nickle=29