Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 14 = 0 Pairs {-2, 7} {2, -7} {-2, -7} {7, 2}

Question
Answer:
we have that

N 1)
a² − 9a + 14 = 0 
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² − 9a)=-14Complete the square  Remember to balance the equation by adding the same constants to each side 
(a² − 9a+20.25)=-14+20.25
Rewrite as perfect squares(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25
a1=4.5+√6.25-----> a1=7a2=4.5-√6.25-----> a2=2the solution problem N 1 is the pair {7, 2}
N 2) a² + 9a + 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 9a)=-14Complete the square  Remember to balance the equation by adding the same constants to each side 
(a² +9a+20.25)=-14+20.25
Rewrite as perfect squares(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25
a1=-4.5+√6.25-----> a1=-2a2=-4.5-√6.25-----> a2=-7the solution problem N 2 is the pair {-2,-7}N 3) a² + 3a − 10 = 0Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 3a)=10
Complete the square  Remember to balance the equation by adding the same constants to each side 
(a² + 3a+2.25)=10+2.25
Rewrite as perfect squares(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25
a1=-1.5+√12.25-----> a1=2a2=-1.5-√12.25-----> a2=-5the solution problem N 3 is the pair {2, -5}
N 4)a² + 5a − 14 = 0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² + 5a) =14
Complete the square  Remember to balance the equation by adding the same constants to each side 
(a² + 5a+6.25) =14+6.25
Rewrite as perfect squares(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25
a1=-2.5+√20.25-----> a1=2a2=-2.5-√20.25-----> a2=-7the solution problem N 4 is the pair {2, -7}
N 5) a² − 5a − 14 = 0Group terms that contain the same variable, and move the constant to the opposite side of the equation(a² − 5a)=14
Complete the square  Remember to balance the equation by adding the same constants to each side 
(a² − 5a+6.25)=14+6.25
Rewrite as perfect squares(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25
a1=2.5+√20.25-----> a1=7a2=2.5-√20.25-----> a2=-2the solution problem N 5 is the pair {7, -2}
solved
general 10 months ago 9149