PLEASE HELP!! SO IMPORTANT! The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70cm^3 of water. Find the percent of the cup that is filled with water after 3 seconds. Use 3.14 for pi and round your final answer to the nearest percent.

Note : The dimensions of the cup are not given.Now we have been given that, after 2 seconds, the cup has a volume of 70 cubic cm.As the cup is filled at a constant rate, in 1 second, it fills [tex]\frac{70}{2}=35[/tex] = 35 cubic cm.Hence, in 3 seconds, it fills [tex]35\times3=105[/tex] cubic cm.To find the percent we need the dimensions of the cup.