Sierra is selling bracelets to raise money for the Language Club at school. Each bracelet with yellow beads sells for $5. Each bracelet with orange beads sells for $6. She raised $660 for the club. The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads. Let y represent the number of bracelets with yellow beads and r represent the number of bracelets with orange beads.Which system of equations will solve for the number of each type of bracelet sold?

Answer:Correct answer is:[tex]5y+6r=660\\y=2r+8[/tex]Step-by-step explanation:Given that Number of bracelets with yellow beads is represented by [tex]y[/tex]Each bracelet with yellow beads is sold for $5.Total money raised by bracelets with yellow beads = Number of bracelets sold [tex]\times[/tex] Money raised by sale of one such bracelet = [tex]5y[/tex]Also Given that Number of bracelets with Orange beads is represented by [tex]r[/tex]Each bracelet with orange beads is sold for $6.Total money raised by bracelets with orange beads = Number of bracelets sold [tex]\times[/tex] Money raised by sale of one such bracelet = [tex]6r[/tex]Given that total money raised by sale of both type of bracelets is $660.so, the first equation becomes:[tex]5y+6r=660 ....... (1)[/tex]It is also given that "The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads"[tex]\Rightarrow r =2r+8 ...... (2)[/tex]So, by equation (1) and (2), the system of equations is:[tex]5y+6r=660\\y=2r+8[/tex]