The equation of a parabola is 1/32 (y−2)2=x−1 .What are the coordinates of the focus?(1, 10)(1, −6)(−7, 2)(9, 2)

The given equation of parabola is[tex] \frac{1}{32} (y-2)^2 = x-1 [/tex]Which can also be written as[tex] x = \frac{1}{32} (y-2)^2 +1 [/tex]Here vertex (h,k) is (1,2)And value of a is[tex] a = \frac{1}{32} [/tex]Formula of focus is[tex] (h+ \frac{1}{4a} , k) [/tex]Substituting the values of h,k and a, we will get[tex] (1+ \frac{1}{4*(1/32) } , 2} = (1+ 8,2) = (9,2) [/tex]Therefore the correct option is the last option .