The five members of the Traynor family each buy train tickets. During the train ride, each family member buys a boxed lunch for $6.50. If the total cost of the trip is $248.50, what is the price of each train ticket?

Let's assume the price of each train ticket is xwe are given total number of family members =5so, total cost of ticket = total number of family members*the price of each ticketso, total cost of ticket =5*xso, total cost of ticket =5xnow, we have each family member buys a boxed lunch for $6.50so, total cost of lunch box = total number of family members*price of each lunch boxso, total cost of lunch box = 5*6.50total cost of trip = total cost of ticket+total cost of lunch boxwe are given total cost of trip is $248.50now, we can plug valuesand we get [tex] 248.50=5x+5*6.50 [/tex]now, we can solve for x[tex] 248.50=5x+32.5 [/tex][tex] 248.50-32.5=5x+32.5-32.5 [/tex][tex] 216=5x [/tex][tex] \frac{5x}{5} =\frac{216}{5} [/tex][tex] x=43.2 [/tex]so, the price of each train ticket is $43.2..........Answer