The great pyramid of giza was constructed as a regular pyramid with a square base. it was built with an approximate volume of 2,592,276 cubic meters and a height of 146.5 meters. what was the length of one side of its base, to the nearest meter

The volume formula for a pyramid is:

V = ah[tex] \dfrac{1}{3} [/tex]

Where a = area of the base and h = height

Now, just plug in the numbers from this formula:

2592276 = a(146.5)[tex] \frac{1}{3} [/tex]

Now, first of all, to find the length of one side of the base, we need to find the area. What you do now is distribution

[tex]2592276 = a(146.5) \dfrac{1}{3}[/tex]

[tex]3 \times 2592276 = a(146.5) \dfrac{1}{3} \times 3[/tex]

[tex]7776828 = a(146.5)[/tex]

[tex] \dfrac{7776828 }{146.5} = \dfrac{a(146.5)}{146.5} [/tex]

[tex]53084.15017 = a[/tex]

The area is 53084.15017m². Now, because the base is a square (because it is a pyramid), plug this in the area formula:

L = length of side
[tex]53084.15017 = L^2[/tex]

Square root both sides, and you get the length of each side of the base as 230.399999999m

Round it to the nearest meter, and it is 230m