The population of a town increased by 16 2/3 % in 1990 and 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?

First, find the population at the end of 1990
At the end of 1990, the increase would be 16 2/3 % of 30,000, or we could write it as
i = [tex]16 \frac{2}{3} [/tex]% × 30,000

We need to change percent into proper fraction
i = [tex]16 \frac{2}{3} [/tex]% × 30,000
i = [tex] \frac{50}{3} [/tex]% × 30,000
percent means per hundred
i = [tex]\frac{50}{3} .\frac{1}{100}[/tex] × 30,000
i = [tex]\frac{50}{300}[/tex] × 30,000
i = 5,000

At the end of 1990, the population would be
p = 30,000 + 5,000
p = 35,000

Second, find the population at the end of 1991
The increase of the population would be 10% of 35,000, or we could write it as
i = 10% × 35,000
i = 0.1 × 35,000
i = 3,500

The population at the end of 1991 would be
p = 35,000 + 3,500
p = 38,500
This is the final answer