The sum of three consecutive odd integers is 76 less then seven times the middle number.Find three integers

The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectivelySolution:Since each consecutive odd integer is separated by a difference of  2 Let "n" be the first integern + 2 be the second integern + 4 be the third integerGiven that the sum of three consecutive odd integers is 76 less then seven times the middle numberWhich means,The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))That is,n + n + 2 + n + 4 = 7(n + 2) - 763n + 6 = 7n + 14 - 764n = 68n = 17So we get:First integer = n = 17Second integer = n + 2 = 17 + 2 = 19Third integer = n + 4 = 17 + 4 = 21Thus the three consecutive odd integers are 17, 19 and 21 respeectively