Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer?

Answer: The price for the computer = $1152Step-by-step explanation:Let the first boy = FLet the second boy = SLet the price of computer = CThe second boy had 5/ 6 of the money the first had. I.eS = 5/6 F Then F = 6/5S ......(1)The first boy had 7 /8 of the price of the computer. That isF = 7/8C ....... (2)Substitute F in (1) into (2)6/5S = 7/8CS = 5/6 × 7/8CS = 35/48C ......(3)Together they had $696.00 more than they need to pay. That isF + S = C + 696 ........ (4)Substitute equation 2 and 3 into 47/8C + 35/48C = C + 6960.875C + 0.729C = C + 6960.604C = 696C = 696/0.604C = 1152 dollars Therefore, the price for the computer = $1152