Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have? { a0quarters, a1dimes }

d = q + 10
10d + 25q = 345 cents
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Substitute for "d" and solve for "q";
10(q+10) + 25q = 345

35q + 100 = 345
35q = 245
q = 7 (# of quarters)
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Since d = q+10, d = 17 (# of dimes)
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Cheers,
Stan H.