What are the excluded values of x for x+4/ -3^2+12x+36

x+4 / -3x^2 + 12x + 36

= x + 4 / -3 ( x^2 - 4x - 12) 

= x - 4 / -3(x - 6)(x + 2)

the excluded values make the denominator = 0  

so they are 6  and -2  Answer