What is the maximum value of the feasible regions if P = 120x + 100yRegion 1 (0 ,5)Region 2 ( 0, 4)Region 3 (4,0)Region 4 (3,0)

Answer:The maximum value of the feasible regions is P=500Step-by-step explanation:we know thatTo find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the resultswe have[tex]P=120x+100y[/tex]Region 1 (0,5)For x=0, y=5substitute[tex]P=120(0)+100(5)=500[/tex]Region 2 (0,4)For x=0, y=4substitute[tex]P=120(0)+100(4)=400[/tex]Region 3 (4,0)For x=4, y=0substitute[tex]P=120(4)+100(0)=480[/tex]Region 4 (3,0)For x=3, y=0substitute[tex]P=120(3)+100(0)=360[/tex]CompareThe maximum value of the feasible regions is P=500