What is the measure of AC ?Enter your answer in the box.°

Solution:we are given that Inscribed angle[tex] =(2.5x+4) [/tex]Intercepted arc[tex] =(7x-2) [/tex]As we know that the Inscribed angle is Half of the measure of the intercepted arc. So we can write [tex] (2.5x+4)=\frac{1}{2}(7x-2) \\\\7x-2=2(2.5x+4)\\\\7x-2=5x+8\\\\7x-5x=8+2\\\\2x=10\\\\x=5\\\\\text{So Measure of arc AC}=(7x-2)=7*5-2=35-2=33 [/tex]