What is the product in simplest form y^2 over y-3 . Y^2-y-6 over y^2+1y

Question
Answer:
Answer:[tex]\frac{y^7-y^6 - 6y^5}{y^2 + 1}[/tex]Step-by-step explanation:To evaluate or simplify expressions with exponents, we use exponent rules.  1. An exponent is only a short cut for multiplication. It simplifies how we write the expression. 2. When we multiply terms with the same bases, we add exponents. 3. When we divide terms with the same bases, we subtract exponents. 4. When we have a base to the exponent of 0, it is 1. 5. A negative exponent creates a fraction. 6. When we raise an exponent to an exponent, we multiply exponents. 7. When we have exponents with parenthesis, we apply it to everything in the parenthesis. Simplify the expression y^2 over y^-3 first using the division rule. It becomes y^5. Then multiply straight across and use the multiplication rule to simplify.[tex]\frac{y^2}{y^{-3}}* \frac{y^2 - y - 6}{y^2 + y}[/tex][tex]y^5 * \frac{y^2 - y -6}{y^2 +1} = \frac{y^7-y^6 - 6y^5}{y^2 + 1}[/tex]
solved
general 10 months ago 2143