Write an equation of the parabola with focus (0, −5/3) and directrix y=5/3I know the formula is y= 1/4p x^2 but i am having trouble with the fractions being implemented.p=-5/3

Given:
The focus is at (0, -5/3)
The directrix is y = 5/3

A standard form of the equation for a parabola is
y = a(x- h)² + k
with the focus at (h , k + 1/(4a)),
and the directrix at y = k - 1/(4a)

Therefore
h = 0                          (1)
k + 1/(4a) = -5/3         (2)
k - 1/(4a) =  5/3          (3)

Add (2) and (3).
2k = 0
k = 0

Therefore the vertex is at (0,0).
From (2), obtain
1/(4a) = -5/3
4a = -3/5
a = -3/20

The equation of the parabola is
y = -(3/20)x²

The graph is shown below.

Answer: [tex]y=- \frac{3}{20} x^{2}[/tex]