Write and solve an inequality for the following: A fish tank can hold at most 315 gallons of water. if a hose is filling the fish tank at a rate of 15 gallons every 10 minutes, how many hours can the hose be left on before the tank overflows?

Step 1Find the unit rate[tex]\frac{15}{10} \frac{gallons}{minute}= \frac{1.5}{1} \frac{gallons}{minute}[/tex]Step 2Convert  [tex]\frac{gallons}{minute}[/tex] to [tex]\frac{gallons}{hour}[/tex]we know that[tex]1\ hour=60\ minutes[/tex]so[tex]\frac{1.5}{1} \frac{gallons}{minute}=\frac{1.5}{(1/60)} =60*1.5=90\frac{gallons}{hour}[/tex]Step 3Find the inequalityLetx--------> the time in hours[tex]90x < 315[/tex] ------> this is the inequalityStep 4Solve the inequality[tex]90x < 315[/tex]Divide by [tex]90[/tex] both sides[tex]90x/90 < 315/90[/tex][tex]x < 3.5\ hours[/tex]thereforethe answer isHose can be left on before tank overflows less than [tex] 3.5\ hours[/tex]