Rewrite 2+ 1/b-2 = 3b/b+2 as a proportion. Which of these proportions is equivalent to the original equation? 3/b-2 = 3b/b+2 2b+3/b-2 = 3b/b+2 2b-3/b-2 = 3b/b+2

Question
Rewrite 2+ 1/b-2 = 3b/b+2 as a proportion. Which of these proportions is equivalent to the original equation? 3/b-2 = 3b/b+2 2b+3/b-2 = 3b/b+2 2b-3/b-2 = 3b/b+2
Answer:
Rewrite 2+ 1/b-2 = 3b/b+2 as a proportion. Which of these proportions is equivalent to the original equation? 3/b-2 = 3b/b+2 2b+3/b-2 = 3b/b+2 2b-3/b-2 = 3b/b+2 651058e037a94.webp
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algebra 10 months ago 5569