A system of linear inequalities is shown below:y − x > 0y − 1 > 0Which of the following graphs best represents the solution set to this system of linear inequalities?

Answer: Graph D represents the given inequality.Explanation: Since, given inequalities, y − x > 0  ------(1) y − 1 > 0    -----(2)And, the intersection point of line (1) and (2) is (1,1)Since, for the line , y-x>0, if x=0 and y=0 then 0>0 (not true)therefore, the area of the line will not comprise the point (0,0)Again, For inequality (2) -1>0(not true) at (0,0) therefore, the area of inequality (2) also does not consist of origin.Thus, after making the common area of inequalities (1) and (2) we found only graph four is the correct graph for the given system.Note: In graph (1) The system does not contains the common area.So, it can not be the graph of the system.In graph (2) the area of the system is missing in second quadrant.So it can not be the graph of the system.In graph (3)  the area of the system is missing in first quadrant.So it can not be the graph of the system.