An object is launched from the ground. The object’s height, in feet, can be described by the quadratic function h(t) = 80t – 16t2, where t is the time, in seconds, since the object was launched. When will the object hit the ground after it is launched? Explain how you found your answer.

Answer:The object hits the ground 5 seconds after being launched.Step-by-step explanation:The height of the object in t seconds after being launched is given by the following equation:[tex]h(t) = 80t - 16t^{2}[/tex]When will the object hit the ground after it is launched?This is t for which h(t) = 0.So[tex]80t - 16t^{2} = 0[/tex][tex]16t(5 - t) = 0[/tex]Then[tex]16t = 0[/tex][tex]t = 0[/tex]This is the launch point[tex]5 - t = 0[/tex][tex]t = 5[/tex]SoThe object hits the ground 5 seconds after being launched.