Calculate the acceleration in m/s2 that is applied so that a car moving in a straight line at 103 km/H reduces its speed to 60 km/h in 1.5

a = (v1 - v0) / t where a is the acceleration, v0 is the initial velocity, v1 is the final velocity, and t is the time taken to change the velocity. First, we need to convert the velocities from km/h to m/s: 103 km/h = 28.61 m/s 60 km/h = 16.67 m/s Substituting the given values into the formula, we get: a = (16.67 m/s - 28.61 m/s) / 1.5 s Simplifying, we get: a = -7.96 m/s² Therefore, the acceleration in m/s² that is applied to the car is -7.96 m/s². The negative sign indicates that the car is decelerating, or slowing down.