Circle M is shown. Line segments J L and H K are diameters that intersect at center point M. Angle K M L is 25 degrees.What is the approximate length of minor arc JH? Round to the nearest tenth of a centimeter.

Answer:Arc(JH) = 0.44rStep-by-step explanation:In this question radius of the circle is not given.Given information: Line segments J L and H K are diameters that intersect at center point M, m∠KML = 25°.Using given information draw a diagram as shown below.From the below figure it is clear that ∠KML and ∠JMH are vertically opposite angles.If two lines intersect each other then vertically opposite angles are equal.[tex]m\angle KML=n\angle JMH=25^{circ}[/tex]Let the radius of the circle M is r.The formula for arc length is[tex]s=2\pi r(\frac{\theta}{360})[/tex]where, r is radius of the circle and θ in degree.[tex]Acr(JH)=2\pi r(\frac{25}{360})[/tex][tex]Acr(JH)=0.436332313r[/tex][tex]Acr(JH)\approx 0.44r[/tex]Note: If the value of r is given, then substitute the value of r in the above equation and round to the nearest tenth of a centimeter.Therefore, the length of arc (JH) is 0.44r.