What is the percentage of sugar in the syrup made of 10 kg of water and 2 kg of sugar?

The percentage of sugar in the syrup is 16.66...% ExplanationThe amount of water in the syrup is 10 kg. and the amount of sugar is 2 kg. So, the total amount of the syrup [tex] =(10+2) kg = 12 kg [/tex]Percentage of sugar = [tex] \frac{(Amt. of sugar) }{(Amt. of syrup)} * 100 [/tex]% [tex] \frac{2 kg}{12 kg} * 100 [/tex]% = [tex] \frac{50}{3} = 16.666... [/tex]% So, the percentage of sugar in the syrup is 16.66...%